Z for 95% confidence interval = Z0.025 = 1.96
p = 71/125 = 0.568
Confidence interval
= (0.49 , 0.65)
Lower limit = 0.49
Upper limit = 0.65
A random sample of 125 adults was given an IQ test. It was found that 71...
A random sample of 225 adults was given an IQ test. It was found that 105 of them scored higher than 100. Based on this, compute a 90% confidence interval for the proportion of all adults whose IQ score is greater than 100. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. What is the lower limit of the 90% confidence interval? What is the upper limit...
STA2023-TR 12:30-545 (158 5po 20ns (12 Time Remaining 2:00 A random sample of 125 adults was given an IQ test. It was found that 70 of them scored higher than 100. Based en this, corpubu 95% corer for the proportion of all aduits whose IQ score is greater than 100. Then complete the table below Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a ist of formulas-) men...
A random sample of 225 adults was given an IQ test. It was found that 130 of them scored higher than 100. Based on this, compute a 95% confidence interval for the proportion of all adults whose IQ score is greater than 100. Then complete the table below.
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In random, independent samples of 200 adults and 400 teenagers who watched a certain television show, 98 adults and 224 teens indicated that they liked the show. Let p1 be the proportion of all adults watching the show who liked it, and let P2 be the proportion of all teens watching the show who liked it. Find a 90% confidence interval for pi-p2. Then complete the table below. carry your intermediate computations to at least three decimal places. Round your...