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A random sample of 125 adults was given an IQ test. It was found that 71 of them scored higher than 100. Based on this, compu

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Answer #1

Z for 95% confidence interval = Z0.025 = 1.96

p = 71/125 = 0.568

Confidence interval p* (1 - p) = (p = 20.025 * V4

                               (0.568 + (1-0.568)、 = (0.568 +1.96 *, 125

                               = (0.568 +0.087)

                               = (0.49 , 0.65)

Lower limit = 0.49

Upper limit = 0.65

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