Question

A 40-year-old male participant has a measured maximal HR of 175 bpm and resting HR of 75 bpm. What is his 60% and 80% of the THR as calculated by the HRR method? (1.0 pts) His resting HR decreases by 10 beats/min after participating in an endurance-training program. Because maximal HR (175 beats/min) is not affected by training, what happens his 60% and 80% of THR?

Answer 1

Answer of the 1st question

Given data:

MHR= 175bpm

RHR=75bpm

We know that

THR = [(MHR - RHR) x %HRR]+RHR

In 60% : THR = [(175-75) x 60%] + 75 =135bpm

In 80% : THR = [(175-75) x 80%] + 75 =155bpm

Answer of the 2nd question :

RHR = 65bpm

MHR = 175bpm

In 60% : THR = [(175-65)x60%]+65 = 131bpm

In 80% : THR = [(175-65)x80%]+65 =153bpm