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6-7 Current Dividers 32. How much branch current should each meter in Figure 6-80 indicate? FIGURE 6-80 RA 1.0 k12 R₂ 2.7k 2
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+ Solution : I 1K2R I 2-7 K2= R2 -o- Us to From the Kirchoffs current law we have, I - 11 + Iz When the circuit is connectedIl R1 = Iz Rz. We know that RA = 1k2 and R2= 207 kr → IL x1 = 207 12 » Il > 20712) - © solving 0 and 6 we get I1 + I2 - 3 (20

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