![51 : 16- 2f1 + 2f2 + P3 8° = 2P, - 7 %3D 8+2f, - (2 -P3 9 = %3D 4P2 -4 . 4 + 4P,- Pz -4P3 23 - 3 Relation betwen geed 1 & goo](//img.homeworklib.com/questions/121a82a0-7931-11ea-acda-a3c9518c843a.png?x-oss-process=image/resize,w_560)
![Pocitively selated auith lathindy de, one anothes as f, rises 8 also sises Hemre, lgeod. 1 and Good 3 are substitales, Relat](//img.homeworklib.com/questions/12b3b4a0-7931-11ea-acb7-7f85182ecf88.png?x-oss-process=image/resize,w_560)
![2p, +2f, - 2f% -P3 16 + 7 こ 4P, -28p - P3 = 23 For こ 8 + 28, - 2 - P3 = 4P2 - 4 8+4 = 4p2 -28, +P2 + P3 こ 5P2 -281 + = 12 92](//img.homeworklib.com/questions/13683560-7931-11ea-a4c7-0df89c714f71.png?x-oss-process=image/resize,w_560)
![B) - 28, + 5 Pz + P3 w) - 4P, + Pz こ 12、 6/3 ) finding tpuilibrium faices and guantities- Ueing the aboue 3 Conditions by O](//img.homeworklib.com/questions/13fa1a10-7931-11ea-921b-91d82d021325.png?x-oss-process=image/resize,w_560)
![From ® & (b) 35 ) x 4 + 3/% - 8P, + 29P2 65 Hi + 122 - K + 29P2 140 こ 65 こ 41P2 205 こ 205 こ 41 2o, こ 5 28, + 3P2 - 35 >» 2P,](//img.homeworklib.com/questions/149e37e0-7931-11ea-bc42-9b73717556d5.png?x-oss-process=image/resize,w_560)
![f - 10 and :5 In Peguation 1 Gqulbriun cenditien - 4P, -2pz - P3 = 23 ) (4x10) - (2x5) - 23 40 - 10 P3 23 P3 = 30 - 23 ond fs](//img.homeworklib.com/questions/1532b640-7931-11ea-b6f2-1fa87fe0241b.png?x-oss-process=image/resize,w_560)
![->83: 23 - 3 =(2x7) - 3 11 こ As under equilibricum So, 8, = 8,° 13 こ 82 = 8, - 16 こ 11 こ So finally we couilude undes Equili](//img.homeworklib.com/questions/15d8d960-7931-11ea-98f1-bf14cf64e38c.png?x-oss-process=image/resize,w_560)
51 : 16- 2f1 + 2f2 + P3 8° = 2P, - 7 %3D 8+2f, - (2 -P3 9 = %3D 4P2 -4 . 4 + 4P,- Pz -4P3 23 - 3 Relation betwen geed 1 & good 2 Fasom 8," Equation 8,4 So as a P2 ue lan see that is faritively related to ie- jsice j dewanded god jie. sises thee guanditey * good 1 ie- Se, Rises Home, beth goeds are substitute f ene amother Aelation betrmeen good I and goord 8 d Guation me ble that fa ie
Pocitively selated auith lathindy de, one anothes as' f, rises 8 also sises Hemre, lgeod. 1 and Good 3 are substitales, Relation betrueen good 2 and good 3 Faom eguation 8, me see that ils negatively selated to Po Po sises them d Hene as falla o Honce, Good 2 and Gpod 3 Aomflmente. are lonelude Good 1 and Good 2 bubetitules are -> and Good 3 dubstitulis Good I oru -> Ond Good 3 2. -> Good lomplemente are 6) Equilibrium Conditione and B3 = 9% 8o, 16 - 20, + 2f2 + P3 = 28, 2P, -7 .
2p, +2f, - 2f% -P3 16 + 7 こ 4P, -28p - P3 = 23 For こ 8 + 28, - 2 - P3 = 4P2 - 4 8+4 = 4p2 -28, +P2 + P3 こ 5P2 -281 + = 12 92 fog 4 + 46, - (2 - 4P3 2Ps - 3 こ 283 - 4P, + Pz t 4P3 4+3 -4p, + P2 +6P3 こ 222 get 3 Equilibrium :- abone me frem 23 i) 4P. - 212 - P3 こ
"B) - 28, + 5 Pz + P3 w) - 4P, + Pz こ 12、 6/3 ) finding tpuilibrium faices and guantities- Ueing the aboue 3 Conditions by O and O 4P, - 2f2 - - 2P, + 5P, HPa = B12 23 2P1 + 3 Pe 35 by using O and ( (-28, + 5P2 + P3 (-4P1 + P2 + 6P3 = 12) x 6 + ) x %3D - 12P, + 30P2 tbP - 72 + 4Pi |- 8Pi + 292 65 こ
From ® & (b) 35 ) x 4 + 3/% - 8P, + 29P2 65 Hi + 122 - K + 29P2 140 こ 65 こ 41P2 205 こ 205 こ 41 2o, こ 5 28, + 3P2 - 35 >» 2P, +(3x 5) 35 35 - 15 20 2P1 ニ 20 = 10 %3D
f - 10 and :5 In Peguation 1 Gqulbriun cenditien - 4P, -2pz - P3 = 23 ) (4x10) - (2x5) - 23 40 - 10 P3 23 P3 = 30 - 23 ond fs -7 Puthing h -10 i Pr = 5 5 Po =10 ; Pz = * : 28, -7 (2x10) 13 4P2 -4 (4и5) - 4 16 it
->83: 23 - 3 =(2x7) - 3 11 こ As under equilibricum So, 8, = 8,° 13 こ 82 = 8,' - 16 こ 11 こ So finally we couilude undes Equilibrium . P, = 10 81 = l2 = 16 82 P3 1)