Question

43. A coin is tossed four times. a) What is the probability of getting four heads? (1 mark) What is the probability of getting exactly two heads? Be sure to show your work. (2 marks) What is the probability of not getting two heads? Be sure to show your work. (2 marks)
and please can u show it that which part is a, b or c? tnx

Answer 1

a) The probability of getting 4 heads

n(s) = 2^4 = 16

A coin is toss means there is only one coin which is toss four times i.e.

= 1÷16

b) let the exactly two head be P(A)

Therefore, A = {HHTT , THHT, TTHH , HTHT, HTTH , THTH}

Therefore from classical definition we get P(A)

= 6÷16 or 3÷8

c) Probability of not getting two head I.e P( B)

P(B) = 1- P(A)

= 1 - ( 3÷ 8)

= 5 ÷ 8