Utility is maximized when MUx/Px = MUy/Py
(a) Px = 4, Py = 2, so budget line: 18 = 4X + 2Y
Qx | MUx | Px | MUx/Px | Qy | MUy | Py | MUy/Py |
1 | 20 | 4 | 5 | 1 | 16 | 2 | 8 |
2 | 16 | 4 | 4 | 2 | 14 | 2 | 7 |
3 | 12 | 4 | 3 | 3 | 12 | 2 | 6 |
4 | 8 | 4 | 2 | 4 | 10 | 2 | 5 |
5 | 6 | 4 | 1.5 | 5 | 8 | 2 | 4 |
6 | 4 | 4 | 1 | 6 | 6 | 2 | 3 |
Possible Utility-maximizing bundles are: A(X = 1, Y = 4), B(X = 2, Y = 5) and C(X = 3, Y = 6).
Total cost, bundle A = 4 x 1 + 2 x 4 = 4 + 8 = 12 (budget is not exhausted)
Total cost, bundle B = 4 x 2 + 2 x 5 = 8 + 10 = 18 (budget is exhausted)
Total cost, bundle C = 4 x 3 + 2 x 6 = 12 + 12 = 24 (budget is exceeded)
So, bundle B exhausts budget with X = 2 and Y = 5.
(b)
Total utility = Utility from 2X + Utility from 5Y = (20 + 16) + (16 + 14 + 12 + 10 + 8) = 96
(c) Px = 2, Py = 2, so budget line: 18 = 2X + 2Y [i.e. 9 = X + Y]
Qx | MUx | Px | MUx/Px | Qy | MUy | Py | MUy/Py |
1 | 20 | 2 | 10 | 1 | 16 | 2 | 8 |
2 | 16 | 2 | 8 | 2 | 14 | 2 | 7 |
3 | 12 | 2 | 6 | 3 | 12 | 2 | 6 |
4 | 8 | 2 | 4 | 4 | 10 | 2 | 5 |
5 | 6 | 2 | 3 | 5 | 8 | 2 | 4 |
6 | 4 | 2 | 2 | 6 | 6 | 2 | 3 |
Possible Utility-maximizing bundles are: A(X = 2, Y = 1), B(X = 3, Y = 3), C(X = 4, Y = 5) and D(X = 5, Y = 6).
Total cost, bundle A = 2 x 2 + 2 x 1 = 4 + 2 = 6 (budget is not exhausted)
Total cost, bundle B = 2 x 3 + 2 x 3 = 6 + 6 = 12 (budget is not exhausted)
Total cost, bundle C = 2 x 4 + 2 x 5 = 8 + 10 = 18 (budget is exhausted)
Total cost, bundle D = 2 x 5 + 2 x 6 = 10 + 12 = 22 (budget is exceeded)
So, bundle C exhausts budget with X = 4 and Y = 5.
(d)
Price | Quantity demanded |
$4 | 2 |
$2 | 4 |
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