Ans) a) 9ml
Explaination:
As available dose of potassium chloride is 60meq which contains 2 meq/ml on lable
Ordered dose: 18meq
2meq = 1 ml
18meq = x
x = 18÷2 = 9ml
9 milliliter of potassium chloride should be added to the IV bag.
b) 9ml ~ 18 meq in NS 1000ml @ 100ml/hr
Means it will take 10 hrs to complete 1 IV bag so for 24 hrs
10 hrs = 1 IV bag
24 hrs = y
y= 2.4 ~ 3 IV bags to be prepared for 24 hrs but while infusing Infuse 2 full IV bags & from 3 rd IV bag only 400ml.
how many milliliter of potassium chloride should ne added to the IV bags? Using the following...
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