Question

11 Calculate the diameter and oil height of a vertical separator for the following conditions Maximum gas flow rate 35 MMscf/d 0.91 Gas compressibility Gas specific gravity 0.70 25000 barrels/day Maximum oil rate Specific gravity of oil Operating pressure Operating temperature Molecular weight of air 0.90 160 psig 105 F 28.97 1 minute Residence time 10.73 psia.ft3/b.mol°R 62.4 lb/ft3 1 at standard contions Universal gas constant Density of water Compressibility factor

Answer 1

Equations 1,2,3,4 are Souders-Brown equations for gas-liquid separators

Notations used

• d = vertical separator diameter, ft
• L = oil height , ft
• Q_g = max gas flow rate, MMscf/d = 35 MMscf/d =35/ 86400 (MMscf/second)
• Q_L = max oil flow rate, barrel/d = 25000 barrel/d = (25000)/(86400) barrel/second
• P = operating pressure, psig = 160 psig
• ρ_l = oil density, lbm/ft³
• ρ_v = gas density, lbm/ft³
• K = Souders-Brown equation constant, feet/sec
• F_G = Fraction of cross section area available for gas flow and F_G = 1 for vertical separators
• V_{g max} = maximum gas flow velocity ft/s
• t = Residence time= 1 min = 60 second
• Specific gravity = density of fluid / density of water

so ρ_l = (Specific gravity) * (density of water) = 0.9 * 62.4= 56.16 lb/ft³

ρ_v = 0.7 * 62.4 = 43.68 lb/ft³

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