A)F = 7.07
p value = 0.0106
Since p value is less than 0.05 , there is sufficient evidence to say that there is difference in the mean of attendance of three divisions.
B)Fisher LSD = √ MSE (1/ni+1/nj)
t cric = 2.593
Reject H0 if |xi (bar) -xj (bar)| > LSD
Difference | Absolute Value | LSD | Conclusion |
---|---|---|---|
x1 (bar)- x2 (bar) | 2135.08 | 1901.04 | Significant difference |
x2 (bar) - x3(bar) | 2878 | 2082.48 | Significant difference |
x1 (bar) - x3 (bar) | 742.92 | 1901.04 | No Significant difference |
Undo Clipboard Font Alignm H1 f Part a. Rearrange the Attendance values for the Anova: Single-Factor...