Question

A rock contains 0.688 mg of #"^206Pb# of every 1000 mg of #"^238U#. How do you calculate the age of the rock?

Assume that no lead was originally present, that all the #"^206Pb# formed over the years has remained in the rock, and that the number of nuclides in the intermediate stages of decay between #"^206Pb# and #"^238U# is negligible.

The exact mass of #"^206Pb# is 205.974449 g/mol and the exact mass of #"^238U# is 238.050784 g/mol.

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A rock contains 0.688 mg of #"^206Pb# of every 1000 mg of #"^238U#. How do you calculate the age of the rock?
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