The difference equation y(n+2) -3y(n+1)+2y(n) = 1 for n 20 has initial conditions y(0)= -1 and...

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The difference equation y(n+2) -3y(n+1)+2y(n) = 1 for n 20 has initial conditions y(0)= -1 and y(1) 1 1. Find the value of y(

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Answer 1

Answer #1

Each step is done one by one.

yCnt2) -3y (nt) +2ycn) = 1 Putlig Pyc2)8yCD +2()= Putaig ya) ya)= y(2)-3-2-1y2)6 Pueang, n =1-sy 9 y(3)-3y(2) t2y ) = ラy(3)-
(2a3712)Y( N3-52 137 e 1-09(77)-) Z-5+37G) (2-0(21-32+2) YC De 6- (8) by(nta) -3y Cnti) +2ycn)=e)u e Hera (E)= E-3E 13 keg it

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The difference equation y(n+2) -3y(n+1)+2y(n) = 1 for n 20 has initial conditions y(0)= -1 and...

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