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can someone help me with this problem? (1 pt) Find the solution of the differential equation...
1) Find the particular solution of the differential equation that satisfies the initial condition. (Enter your solution as an equation.) Differential Equation Initial Condition yy' − 4ex = 0 y(0) = 9 2) Find the particular solution of the differential equation that satisfies the initial condition. (Enter your solution as an equation.) Differential Equation Initial Condition 10xy' − ln(x5) = 0, x > 0 y(1) = 21 Just really confused on how to do these, hope someone can help! :)
Find the solution of the differential equation dy dx = x y that satisfies the initial condition y(0)=−7. Answer: y(x)=
Find the stable equilibrium solution of the following differential equation: + y - 1 = e2( y − 1). The stable equilibrium solution is y = Check Find the general solution to the differential equation: x + y - x115 = 0. Answer: y(x) = Check Solve the initial-value problem: dy = e ** - y, yO= dx Answer: y(x) = Check
can someone help me to solve this question 5
Question#5 a) Solve the following initial-value problem: (2xcos y + 3x’y)dx +(x? – x’sin y- y)dy =0, where y(0) = 2. [5 marks] b) Find the general solution to the following differential equations: [5 marks] [5 marks] dx
5. Find the solution of the differential equation that satisfies the given initial condition dy cos' xsin dx ysin y Yo) - 1. Leave the answer in the implici form. ,y(o)- 1. Leave the answer in the implicit form.
5. Find the solution of the differential equation that satisfies the given initial condition dy cos' xsin dx ysin y Yo) - 1. Leave the answer in the implici form. ,y(o)- 1. Leave the answer in the implicit form.
15. [-75 Points] DETAILS LARCALCET7 5.8.061.MI. Find the particular solution of the differential equation that satisfies the initial condition. 1 dy dx = y(0) = 21 y =
correct me if wrong
Verify by substitution that y is the solution for the differential equation Y' + 4y = 1.4 The solution is y = Cel-4x) + 0.35 Where the initial Condition (IC) is given by: y(x=0) = 2 y = dy +4y=114 Cdx) dx dy +4y= 1.46dx) dy +4(2)=11444 dy +8=1,4dx
Find the particular solution of the differential equation that satisfies the initial condition. (Enter your solution as an equation.) Differential Equation initial Condition y(x + 3) + y = 0 Y(-6) = 1
Find the function y=y(x) (for x>0) which satisfies the separable differential equation dy/dx = (4+17x)/(xy^2). ;x>0 with the initial condition: y(1)=2
II. Find the solution of the differential equation that satisfies the given initial condition du 2t +sec2 t dt 2uu(0-5 di 1. 2·y' + y tan x = cos2 x, y(0) =-1 dy 6. ( In,() 10