Question

Instructions Answer all four questions in Part I 50 Points for Question 1. Briefly describe the difference between a binary bypass branching routine, a routine that is a binary choice, and a multiple branching routine. Use the appropriate routine to calculate and print pay for an employee. The employees pay is rate * hours if they work forty hours or less. If the employee works more than forty hours, the pay is calculated as rate * hours for the first hours forty and double time for hours over forty Assume the following declarations Double pay Double final rate 10.00; Double hours 44;

Answer 1

Binary Routine:

Binary branching is a two way decision statement , when we need to take a decision based on condition is true of false.

If condition is true , control takes branch1 or

if condition is false , control takes branch 2.

In Multiway branching, there is a possibility of multiple conditions that is more than two , if a particular condition is true, that particular block is taken.

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//Routine for computing pay using binary choice
void binarybranch(double final_rate, double hours){
double pay,pay1,pay2;
  
if(hours<=40)
pay=hours*rate;

else
{
overtime=hours-40;
pay1=40*final_rate;
pay2=overtime*2*final_rate;
pay=pay1+pay2;
}
cout<<"Total pay:"<<pay<<endl;
}

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//Routine for computing pay using multiple branching choice
void multi_way_branch(double final_rate, double hours)

{
double pay,pay1,pay2;
  
if(hours<=40)//branch1
pay=hours*rate;

else if(hours>40 &&hours<50)//branch 2
{
overtime=hours-40;
pay1=40*final_rate;
pay2=overtime*2*final_rate;
pay=pay1+pay2;
}
else if(hours>=50&&hours<60)//branch3
{

overtime=hours-40;
pay1=40*final_rate;
pay2=overtime*3*final_rate;
pay=pay1+pay2;
}
else //branch 4
{
overtime=hours-40;
pay1=40*final_rate;
pay2=overtime*3*final_rate;
pay=pay1+pay2;
}

cout<<"Total pay:"<<pay<<endl;
}