Light of wavelength 588.0 nm is incident on a narrow slit. The diffraction pattern is viewed...

Question

Question

$Light of wavelength 588.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 83.5 cm from the sli$

Answer 1

Answer #1

twe know that the tmstraehen mter ferenee ocecur when a smo-na sals fred 588 nm. 83.5 em a- n1.37 em. 3 X588 NG9 1-37 XIC 2-

Answer 2

Answer #2

SOLUTION :

Let the width of slit be a meters.

As per following formula,

Distance between 3rd order minimum and central maximum

= Order of minimum * Wave length * Distance of screen from the slit / Width of slit

=> 1.37 * 10^(-2) = 3 * 588*10^(-9) * 83.5*10^(-2) / a

=> a = 3 * ( 588*10^(-9) * 83.5) / 1.37

=> a = 1.075 * 10^(-4) m = 0.1075 mm (ANSWER).

answered by: Tulsiram Garg

Answer 3

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