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ReviewI Constants Part A An underwater diver sees the sun 53° above horizontal. How high is the sun above the horizon to a fi

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Answer #1

From snell's law

n_{air}Sin\theta _{air}=n_{water}Sin\theta _{water}

1\times Sin\theta _{air} =1.33Sin(90-53)

\theta _{air}=Sin^{-1}(0.8004)=53.17^{o}

From horizontal

\phi =90-53.17=36.83^{o}

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