The half-life for the process 238U→206Pb is 4.5×109yr. A mineral sample contains 61.0 mg of 238U...
The half-life for the process 238U→206Pb is 4.5×109yr. A mineral sample contains 61.0 mg of 238U and 14.5 mg of 206Pb.
What is the age of the mineral?
To calculate the age of the mineral, begin by rearranging the first-order relationship between the half-life, t1/2, and the decay constant to solve for the decay constant, k.
k=0.693/t1/2
Then, use the following formula to solve for the age of the mineral, t:
t=−1klnNtN0
where N0 is the original amount of 238U (at time zero) and Nt is the amount remaining after the time interval.
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