Question

Hello, please answer this question correctly. Also, provide the information on how the graph was done in Excel (so I could learn it)

Part I. The rate of the second-order decomposition of acetaldehyde (CH,CHO) was measured over temperature range 700-1000 K, and the rate constants are reported below. Find Ea and A using the data below. Show clearly your excel graph to get full credit. IT. (K) 700 1730 1760 1790 810 840 910 |1000 | K (dm 0.011 0.035 0.105 0.343 0.789 2.17 20.0 145 mol's

Answer 1

K	T	lnK	1/T
0.011	700	-4.50986	0.001429
0.035	730	-3.35241	0.00137
0.105	760	-2.25379	0.001316
0.343	790	-1.07002	0.001266
0.789	810	-0.23699	0.001235
2.17	840	0.774727	0.00119
20	910	2.995732	0.001099
145	1000	4.976734	0.001

InK vs 1/T 0.0002 0.0004 0.0006 0.0008 0.001 0.0012 0.0014 0.0016 -2 -4 ys-22651x + 27.707 -6

form curve Ea/ R = -slope = 22651

so, Ea = 22651 *8.314= 188320 J/mol

now A= e^intercept = e^27.707 = 1.0789 * 10¹²

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