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4. -/1 points OSUniPhys1 32.3.P.029. For the circuit shown below, what are the following? (200 V)sin(1207) 8.00 + 430 pF 0000
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Answer #1

The capacitive reactance is given by, sc27f0 (1207)(430x10ⓇF) = 6.16922 The inductive reactance is, X2 = 21 fL X, = @L =(1207

b) The phase angle between the current and emf is, -1 15.0799-6.1692 8.022 =0.839 rad The maximum current in the circuit is,

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4. -/1 points OSUniPhys1 32.3.P.029. For the circuit shown below, what are the following? (200 V)sin(1207)...
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