Given that,
mean =
= 200
standard deviation =
= 25
middle 90% of score is
P(-z < Z < z) = 0.90
P(Z < z) - P(Z < -z) = 0.90
2 P(Z < z) - 1 = 0.90
2 P(Z < z) = 1 + 0.90 = 1.90
P(Z < z) = 1.90 / 2 = 0.95
z ± 1.65 using z table
Using z-score formula
x= z *
+
x=1.65 *25+200
x= 241.12
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