Question

195x65 AI3 421- C2220 02 The yo chi ni 03. Ale of H of 7.5 the no rth ocaa Doua Can Bala ww 95. W The coco vente : Dolo Collowed to chill them of 01Avev o do . 1993 The the The Y - STP Sola ris 42% KS & wam 23 de 25 t h 14.11 CLB of the water O. A Q12. Man b y sy a 25 ccording CH3CHAUS 2554 Di i ng th ical recor 063Gim AND 455 Three HD 014 do 1L the work by the ws 26170270640 zC₂ Hot 200 4COog + 6H2Ogg the o ne

Answer 1

#1. Mole concept ;

1 mole of every substance in UNIVERSE = molar mass of that substance = 6.022×10^23 atoms/ions/molecules (Avogadro's no.)

So now as , 1 mole of carbon dioxide (CO2) = 44g/mol (molar mass)

So , 44g CO2 have molecules = 6.022×10^23 molecules

Then 154g CO2 will have molecules = (6.022×10^23molecules/44g CO2) × 154g CO2 = 2.11×10^24 molecules of CO2

Option D is correct .