solution
1.
a.)18=μ
b.)48=n
c.)17=x̅
d.)4.5=s
e.) 0.05=α
2.)Null Hypothesis, H0: μ=18
Alternative Hypothesis, H1 : μ ≠ 18
3.) Two Tailed Test
4.)Significance Level(α)=0.05
5.)Test Statistic(t):
6.) degree of freedom (df)=n-1=48-1=47
7.)p-value=2*[P(t<-1.54, df=47])=.1303 (use student t table)
8.) P-value is greater than the significance level(α=0.05), we fail to reject the null hypothesis H0
9.)we fail to reject the null hypothesis H0, There is no enough evidence to support the claim.
I have solve 9 parts of the problem here for the rest please repost
CCSF Introductory Statistics Econ. 5 Chapter 10 Practice Assignment Name: Harry's Hamburgers claims that the residents...
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1. A personnel director from Hawaii claims that the mean household income is the same in Kauai County and Maui County. In Kauai County, a sample of 30 residents has a mean household income of $56,900 and a standard deviation of $14,100. In Maui County, a sample of 30 residents has a mean household income of $59,800 and a standard deviation of $7700 At005, can you reject the personnel director's claim? Assume the population varianccs arc not cqual. (o) Which...
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