Homework Answers
Since the plank is in equilibrium, Net torque about O will be zero, also net vertical and horizontal forces will be zero.
Let coefficient of friction by ground be u, normal by ground be N1, normal by roller be N2,
Force equation in vertical, N1 + N2 cos theta - W = 0 where W is weight
or N1 + N2* sin 70 degree -348 =0
Force equation in horizontal, friction - N2 cos theta = 0 or uN1 - N2 cos theta = 0
or u*N1 - N2* sin 70 degree = 0
Torque equation in about lower point, W*(L/2)cos theta - N2*h/sin theta = 0
348*7.41/2*cos 70 degree - N2*4.77/sin 70 degree = 0
solving the three equations and three unknowns(u,N1,N2), we get u = 0.256 no unit ANSWER
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