Explanation: Bromination of an aryl ring in the presence of a Lewis acid (Here, it is FeBr3) is directed mainly by the substituents present in it. In this case, we have a methyl group and an acyl group in a benzene ring that are para to one another. The attacking position of the electrophile is directed by the strong deactivating group i.e. the acyl group. Hence, the incoming electrophile has only two relatively electron rich carbons in the benzene ring to attack which are ortho to the methyl group and meta to the acyl group. Since the ring is deactivated by the acyl substituent despite having an activating methyl group, the first bromination step would be slower than the subsequent one. In this reaction, the exact amount of Br2 added is not specified. Hence, a possible major product is 3,5-dibromo-4-methylacetophenone.
Draw the major organic product of the below reaction. Do not draw inorganic side products. H3C...
Question 3 of 9 (1 point) Draw the major organic product of the below reaction. Do not draw inorganic side products. Br2 H3C CH3 FeBr3
For the following reaction, draw the major organic product(s). Do not draw inorganic side products. CH3 HNO3 conc. H2SO4
For the following reaction, draw the major organic product(s). Do not draw inorganic side products. .CH3 HNO3 conc. H2SO4 I-Z
For the following reaction, draw the major organic product(s). Do not draw inorganic side products. Please explain .сCH, HNO3 conc. HSO4
For the following reaction, draw the major organic product(s). Do not draw inorganic side products. 1st attempt W! See Periodic Table See Hint AICI3
Draw the major product(s) that result from the following reaction. Do not draw inorganic side products. Draw the major product(s) that result from the following reaction. Do not draw inorganic side products.
Draw the organic product that results from the following reaction. Do not draw inorganic side products.
For the following reaction, draw the major organic product(s). Do not draw inorganic side products. > 2nd attempt v 1st attempt Feedback I- Ź CHE HNO3 conc. H2S04
Draw the organic product of the below reaction. Do not draw inorganic by-products or counterions.
Draw a structural formula for the major organic product(s) of the reaction shown below. (*OWL did not accept the answer below so I know it must be the other product that it produces, but I'm not sure what that is) Draw a structural formula for the major organic product(s) of the reaction shown below. 1. CH3I (excess) 2. Ag20, H20, heat You do not have to consider stereochemistry. Do not draw inorganic by-products. Draw one structure per sketcher. Add additional...