The probability that a student prefers the gym to walking outside in the summer is .36. What is the probability that of two students randomly chosen, exactly one prefers the gym to walking outside?
a. |
.4608 |
|
b. |
.8704 |
|
c. |
The correct answer does not appear as one of the choices |
|
d. |
.2304 |
|
e. |
.4096 |
p = 0.36
n = 2
It is a binomial distribution.
P(X = x) = nCx * px * (1 - p)n - x
P(X = 1) = 2C1 * (0.36)^1 * (0.64)^1 = 0.4608
Option - a is correct.
The probability that a student prefers the gym to walking outside in the summer is .36....
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