Question

The Try to Have Just One (THJO) sunflower seed company roasts and seasons sunflower seeds (in shell). For their production,
500 4 400 7 89 10 11 12 13 14
*NOTE-Equations and calculations are tangible ways to implement a concept, but note that the concept is important as well-be
Annual Ordering Costs Annual Holding Costs Total Costs [1] Finally, determine the current cycle service level (based on curre
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Answer #1

Lead time (L) = 3 days

Average daily demand (d) = 50

Standard deviation of daily demand (sigmad) = 24.45

Number of working days = 365

Annual demand (D) = 365*50 = 18250

Price (P) = 48

Ordering cost (S) = 40

Inventory holding cost (H) = 0.21*48 = 10.08

1.

The sawtooth diagram is shown below

500 4 400 Order quantity ROP 200 Lead time 100 Safety stock 6 7 89 10 11 12 13 14

2.

The formulas

EOQ or Q = sqrt(2DS/H)

Annual ordering cost = DS/Q

Annual holding cost = HQ/2 + safety stock*H

Safety stock = ROP – daily demand*lead time (this means our current safety stock is 50)

Also

Ideal safety stock = z*sigmad*sqrt(L)

Now using these formulas we can calculate the values ( the two columns can be filled with the following info)

Current order quantity

Order quantity (Q)= 300

Annual ordering cost = 18250*40/300 = 2433.33

Annual holding cost = 10.08*300/2 + 50*10.08 = 2016

Total cost = 2433.33 + 2016 = 4449.33

Optimal order quantity

Order quantity (Q) = sqrt(2*18250*40/10.08) = 380.58 or 380 units

Annual ordering cost = 18250*40/380 = 1921.05

Annual holding cost = 10.08*380/2 + 50*10.08 = 2419.2 (assuming that we still maintain same safety stock)

Total cost = 1921.05 + 2419.2 = 4340.25

3.

Currently the safety stock is 50. This means the z value is

50 = z*24.45*sqrt(3)

Or, z = 1.18

This means the current service level is P(z = 1.18) = 0.8809 or 88.09%

If we want 97.5% service level then the z value will be 1.95

This means the safety stock should be 1.95*24.45*sqrt(3) = 82.57 or 83 units

At 97.5% service level the safety stock should be 83 and the reorder point should be 150+83 = 233 boxes.

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