Question Completion Status: QUESTION 1 Suppose the average tread-life of a certain brand of tire is...
Show all work S. The tread life a certain brand of tires is known to be normally distributed with a mean of 50,000 miles and a standard deviation of 4,500 miles a) Determine the probability that a randomly selected tire will last longer than 62,000 miles ANSWER b) The company wishes to set the warranty so that warranty mileage be? only 3% of the tires will need to be replaced, what should the ANSWER
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 2000 miles. What is the probability a certain tire of this brand will last between 55,800 miles and 56,400 miles?
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 1600 miles. What is the probability a randomly selected tire of this brand will last between 56,640 miles and 57,120 miles? i cant seem to figure this out or even know where to begin!... i would be so,so,so greatful if someone would point me in the right direction and at...
The tread life of a particular tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 2000 miles. What is the probability that a randomly selected tire of this brand will last longer than 58,000 miles?A.0.7266, B.0.8413, C.0.1587, D.0.2266
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 3000 miles. What warranty should the company use if they want 96% of the tires to outlast the warranty
8. Tires become illegal when their tread depths fall below a certain value. A particular brand and model of tire has lifespans (number of miles that can be driven before they become illegal) that are approximately normal in distribution with mean 34,000 miles and standard deviation 3,800 miles. Use this information (and tables as needed) to answer parts a-c below. a) Determine the probability that a single tire, selected at random, has a lifespan of between 30,000 and 40,000 miles....
The mileage that car owners get with a certain kind of radial tire is normally distributed with a mean of 70,000 miles. If 97.725% of these tires lasted less than 78,000 miles, please calculate the standard deviation for the tire mileage. [Note: Please round your result for the standard deviation to the nearest integer.] [2 points] What is the probability a randomly selected tire of this type will last 65,000 miles? Please justify your answer. [1 point] Calculate the probability...
1. An automobile tire manufacturer would like to claim that the tread life (in miles) of a certain type of tire is greater than 30,000 miles. Assuming a normal population with 1500 miles answer the following for a test of the hypotheses Ho :-30,000 versus Ha : μ > 30,000 a) Ifa -.01 specify the rejection region as an inequality involving the value of the test statistic b) Based on a sample size of n 25, the corresponding rejection region...
Question Completion Status: QUESTION 10 A multiple choke test has 20 questions each question has 5 choices. What is the distribution of the number of correct answers obtained by a person guessing at random? Poisson Binomial Hypergeometric Geometric QUESTION 11 A company produces 5 defective parts. Ten parts are randomly selected. What is the probability that at least one of them will be defective? O 0.4013 0.6849 O 0.3151 0.5987 QUESTION 12 05 x for 0<x . if the probability...
Suppose you work at a large tire distribution center. The tires' average tread life has been 50,000 miles with a standard deviation of 5,000 miles At the end of the year, the company can reevaluate their supply contract. There are four supply options for the next contract the current supplier or one of three competitors The current supplier produces tires with an average tread life of 50,000 miles with a standard deviation of 5,000 miles Competitor A claims to produce...