Question

Question 1 --/5 ) In synthesising a square wave using Fourier synthesis with four frequencies, why would we be unable to obtain a perfect square wave? (1) because the synthesis was performed in the time domain (2) because it is not possible to add sinusoidal signals (3) because amplitude errors in the signal generator would make the peaks rounded rather than flat because four frequencies are not enough Question 2 (-15) A discrete-time signal is x[n] =1.3nu[n], defined for all integers n. Considering a region of convergence z>1.3, what is the Z-transform X(z)? 1/(1.3-2-1) 2 (1.32-1)n z/(z-1.3) 2 1.3/(1-z-1)

Answer 1

Sam 1 A square ware using fourier Synthesis with four frequency will unable to obtain a perfect square ware because when 3/g xlt is desconth at some interval alt = n inwot xelt) = ane h-oo Value of signal alt cannot be recovered a those instant of time where signal es desconto and if signal does not have any discontinuity then Amplitude of signal can be recovered from its exponential Coofficient. So, the correct option will be (3) Salh 2. x {n} = (13)uen) *(z)= a (1) z = $(1.3) nad -1+ log +(1.397... [Sum of os 65.4] Maine • Ž-13, so current option is ③