Question

A study is conducted to investigate the impact of depression on a patient’s ability to survive cardiac disease. They evaluated 477 participants for depression and followed for 4 years. There were 374 patients with no depression (ND) and 69 of them died. Out of 103 patients with minor or major depression (D), 28 died. Construct a 95% confidence interval for the difference in proportion of deaths between depressed patients with cardiac disease and non-depressed patients with cardiac disease. A) (0.0392, 0.1356) B) (-0.0072, 0.1818) C) (0.0080, 0.1666) D) (-0.0371, 0.2118) E) (-0.0572, 0.2320)

Answer 1

using minitab>stat>basic stat>two proportions

we have

Test and CI for Two Proportions

Sample X N Sample p
1 28 103 0.271845
2 69 374 0.184492

Difference = p (1) - p (2)
Estimate for difference: 0.0873527
95% CI for difference: (-0.00713472, 0.181840)
Test for difference = 0 (vs ≠ 0): Z = 1.95 P-Value = 0.051

option B is true

a 95% confidence interval for the difference in proportion of deaths between depressed patients with cardiac disease and non-depressed patients with cardiac disease is   (-0.0072, 0.1818)