Question

Water, initially saturated vapor at 11.5 bar, fills a closed, rigid container. The water is heated until its temperature is 200°C. For the water, determine the pressure at the final state, in bar.

Answer 1

water Container is rigid, so volume of is constant initial state i final state P = 11.5 bara 1150 kPa ! Tz=206c dry sati kJ/kg kJ/kg *_ TABLE A-5 Saturated water-Pressure table (Concluded) Specific volume, Internal energy, m3/kg Sat. Sat. Sat. Sat. Sat. Press. temp., liquid, vapor, liquid, Evap., vapor, P kPa Tsat °C VF Up Utg ug 1100 184.06 0.001133 0.17745 779.78 1805.7 2585.5 1200 187.96 0.001138 0.16326 796.96 1790.9 2587.8 KJ/KS" KIKEK Enthalpy, kJ/kg Sat. Evap., vapor, hie ha Entropy, kJ/kg.K Sat. liquid, Evap., vapor, St Ste se Sat. liquid, hi Sat. 781.03 798.33 1999.6 1985.4 2780.7 2.1785 4.3735 6.5520 2783.8 2.2159 4.3058 6.5217 1150 Ts, Og, 200. sos 2 - 1150 is mid point of 1100 & 1200. - tsi = 184.06+(187.96-184,00) - Tsi=18 b.olc > 109.15 0.17945+ (0-163265017745) vgi=0; 170355 m3/kg ta=vg, = 0.170355 milky Now, Tz >Ts, so final state of steen is super heated - Also, -21=0.170355 mg

TABLE A-6 Superheated water (Concluded) V u h S uh S °C m3/kg kJ/kg kJ/kg kJ/kg.K | m3/kg kJ/kg kJ/kg kJ/kg.K. P= 1.00 MPa (179.88°C) P= 1.20 MPa (187.96°C) Sat. 0.19437 2582.8 2777.1 6.5850 0.16326 2587.8 2783.8 6.5217 200 0.20602 2622.3 2828.3 6.6956 0.16934 2612.9 2816.1 6.5909 250 0.23275 2710.4 2943.1 6.9265 0.19241 2704.7 2935.6 6.8313 300 0.25799 2793.7 3051.6 7.1246 0.21386 2789.7 3046.3 7.0335 350 0.28250 2875.7 3158.2 7.3029 0.23455 2872.7 3154.2 7.2139 400 0.30661 2957.9 3264.5 7.4670 0.25482 2955.5 3261.3 7.3793 500 0.35411 3125.0 3479.1 7.7642 0.29464 3123.4 3477.0 7.6779 600 0.40111 3297.5 3698.6 8.0311 0.33395 3296.3 3697.0 7.9456 700 0.447833476.3 3924.1 8.2755 0.37297 3475.3 3922.9 8.1904 800 0.49438 3661.7 4156.1 8.5024 0.41184 3661.0 4155.2 8.4176 900 0.54083 3853.9 4394.8 8.7150 0.45059 3853.3 4394.0 8.6303 1000 0.58721 4052.7 4640.0 8.9155 0.48928 4052.2 4639.4 8.8310 1100 0.63354 4257.9 4891.4 9.1057 0.52792 4257.5 4891.0 9.0212 1200 0.67983 4469.0 5148.9 9.2866 0.56652 4468.7 5148.5 9.2022 1300 0.72610 4685.8 5411.9 9.4593 0.60509 4685.5 5411.6 9.3750

rusing steam table - at V2 & Tz=200c at 200°C v (m/k) , P (MPa) 0. 20602 0016934 11.20 V=0./70 355 using interpolation P-1 20170355 -0.20602 1.2-1 0.16934-0. 20602 P = 1.19 4465649 MPa P2 = 12.945 bar

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