You have 5.0 g of Salicylic acid(138.12 g/mol), which is 90% pure. Calculate the number of moles of aspirin formed when the actual yield is 75%.
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Answer :-
Firstly from the preparation of aspirin from salicylic acid, it is evident that one mol salicylic acid produces one mol aspirin. So, simple concept of stoichiometry is used to calculate the moles of aspirin produced.
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You have 5.0 g of Salicylic acid(138.12 g/mol), which is 90% pure. Calculate the number of...
When you are taking 5.0 g of Salicylic acid(138.12 g/mol) for the synthesis of aspirin, what should be the theoretical yield in a) moles? b) mg? Please explain well and show all work!
Aspirin can be prepared from salicylic acid (C7H6O3C7H6O3), which has a molar mass of 138.12 g/mol, and acetic anhydride (C4H6O3C4H6O3), which has a molar mass of 102.04 g/mol. The density of acetic anhydride is 1.082 g/mL. C7H6O3+C4H6O3⟶C9H8O4+C2H3O2C7H6O3+C4H6O3⟶C9H8O4+C2H3O2 What is the yield of aspirin (C9H8O4C9H8O4), which has a molar mass of 180.15 g/mol, possible when reacting 2.02 g of salicylic acid with 1.07 mL of acetic anhydride?
Aspirin can be prepared from salicylic acid (C7H6O3), which has a molar mass of 138.12 g/mol, and acetic anhydride (C4H6O3), which has a molar mass of 102.04 g/mol. The density of acetic anhydride is 1.082 g/mL. C7H6O3+C4H6O3⟶C9H8O4+C2H3O2 What is the yield of aspirin (C9H8O4), which has a molar mass of 180.15 g/mol, possible when reacting 2.18 g of salicylic acid with 1.05 mL of acetic anhydride?
In the reaction of 1.29 g of salicylic acid (138.12 g/mol) with 2.77 g of acetic anhydride (102.10 g/mol), a student obtained 1.09 g of acetylsalicylic acid (180.17 g/mol). What is the percent yield?
The synthesis of aspirin was performed using 2.253 g of salicylic acid and 5.0 mL of acetic anhydride. Calculate the number of moles of salicylic acid. Remember significant figures. a. 0.016 moles b. 0.01633 moles c. None of the other options are acceptable d. 0.02207 moles e. 0.01631 moles
Calculate the number of moles of each of the reagents used: salicylic acid. 4.9 grams used Molecular Weight: 138.12 g/mol Density: 1.443 g/mL
did I do his right? acetyla ley ocid MECHER 10) Calculate the molecular mass of salicylic acid (show your work) 108.09g Cq 960) = 9612.011) 8.064 64.00 HS -> 8CH) = 41.00) op --> 4CO) - 4 C16.0) 180.163 g/mol (4 pts) 19 i 2g of salicylic acid used in the experiment, determine the number of moles of salicylic acid (show your work) nem 0-01447 moles M > 2.009 138113gimo (6 pts) 1g) If2g of salicylic acid produces the same...
10. Calculate the theoretical yield of aspirin using 4.00 g of salicylic acid as the starting material. Assume acetic anhydride is in excess. (Hint: from the mass of salicylic acid acid use, how many moles of salycilic acid are present intitially? What is the salycilic acid : acetylsalicylic acid molar ratio? How many moles of acetylsalicylic acid are formed assuming 100% yield? Based on this abount of moles, how many grams of acetylsalicylic acid are formed? (this is the theoretical...
What is the theoretical yield of aspirin (180g/mol) from the reation of 2.0 g salicylic acid (138g/mol) with 5.0 mL of acetic anhydride (d=1.082g/mL, 102 g/mol)?
QUESTION 1 Aspirin (10.0 g) was saponified with NaOH. After workup, 8.5 g crude salicylic acid was isolated. What is the percent yield of the crude product? 110% 153% 90% 65% QUESTION 2 Aspirin (10.0 g) was saponified with NaOH. After workup, 8.5 g crude salicylic acid was isolated. The product was further purified and only 5.0 g were isolated. Calculate the percent recovery from the purification step. 170% 90% 65% 59% QUESTION 3 Aspirin (10.0 g) was saponified with...