Radius of the disk is r = 2.13m
mass of the disk is m = 185 kg
angular speed is ω_0 = 0.631 rev /s
= 3.96 rad /s
mass of the person is M = 59.4 kg
speed v = 3.31 m/s
Moment of inertia is I = 1/2 mr^2
= 1/2 * 185 kg * ( 2.13m)^2
= 419.7 kg m^2
Initial angular momentum is L = I ω + M r v
= 419.7 kg m^2 * 3.96 rad /s + 59.4 kg * 2.13m * 3.31 m/s
= 2080.79 kg m^2 /s
Final angular momentum is L = Iω + mr^2
= 419.7 + 59.4* ( 2.13m)^2
L = 689.19
final angular speed is ω_f = 2080.79 kg m^2 /s / 689.19
= 3.02 rad /s (Answer)
I hope help you !!
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