Question

TTS 15 allePL J UI 4. Score on last attempt: (0.25, 0.25, 0.25, 0.25), Score in gradebook: (0.25, 0.25, 0.25, 0.25), Out of: (0.25, 0.25, 0.25, 0.25) The trustees of a local school district commission a survey to determine voter opinions about a possible bond measure to fund school upgrades. In a poll of 293 of the district's 5,019 registered voters, 178 would support the bond measure. A hypothesis test was conducted using StatCrunch to determine if such a bond would pass with the required 55% of the vote. One sample proportion hypothesis test: p: Proportion of successes Ho : p = 0.55 HA:p > 0.55 Hypothesis test results: Proportion Count Total Sample Prop. Std. Err. Z-Stat 178 293 0.60750853 0.029063893 1.9786933 P-value 0.0239 Hint 1 Hint 2 Which of the following interpretations of the p-value as a probability statement for the scenario is NOT CORRECT? This p-value of 0.0239 tells us that it is very unlikely to get data like those observed, assuming Ho is true. (This is the least precise description of the four given here.) The p-value is the probability of that a randomly sampled person in this data set supported the bond measure, assuming the null hypothesis is true. The p-value is the probability of observing a sample proportion of 0.6075 or higher in a random sample of size 293 when the true population proportion is 0.55. The p-value is the probability of observing a test statistic as large as 1.9787 or larger, assuming Ho is true. The p-value is the probability of observing a sample proportion that is 1.9787 standard deviations or more above po = 0.55, assuming that the true population proportion is 0.55. Submit License Question 43. Points possible: 1 This is attempt 1 of 4.

Answer 1

| Solution: Paralue = 0.0239 e 0.05 15%) Hence, [A. This p-value of 0.0239 tells us that it is very unlikely to get data like chose ob served, assuming Ho is true.