In the coal-gasification process, carbon monoxide reacts with water to produce carbon dioxide and hydrogen gas.
CO (g) + H2O (g) CO2 (g) + H2 (g)
In an experiment, 0.35 mol of CO and 0.40 mol of H2O were placed in a 1.00-L reaction vessel. At equilibrium, there were 0.22 mol of CO remaining. Keq at the temperature of the experiment is ________.
Group of answer choices
5.5
0.28
0.75
3.5
1.0
CO + H2O CO2 + H2
Initial 0.35 0.40 0 0
Equilibrium. 0.35-x 0.40-x x x
Now, 0.35-x = 0.22
x = 0.35-0.22 = 0.13
So, [H2O] = 0.40-0.13 = 0.27
Keq = [CO2][H2]/[CO][H2O]
= 0.13×0.13/0.22×0.27
= 0.28
Answer is 0.28
In the coal-gasification process, carbon monoxide reacts with water to produce carbon dioxide and hydrogen gas....
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