Question

asap please

write a program that will: Have an array that can hold up to se0 Integers Put 30 random integers from e to 100 into spots 0-29 of the array Print the n Print the nu Report the MEAN Report the MEDIAN. [you may "hard-code" for 30 values situation] [Extra Credit] Report the MODE (S) Report the Minimum. Report the Maximum. Report the Range. [Extra Extra Credit Report the standard Deviation s in original random order. s in sorted order. Insert Length: 180 Lines:35 Line: 5 Col: 1 HP Compaq LA2006x

Answer 1

//since you have not given the programming language, I am doing it in C language. Programming logic remains same for c++, you can use same code if it is for c++

#include <stdio.h>
#include<time.h>
#include <stdlib.h>
#include<math.h>
#include<stdlib.h>

void print(int arr[], int n);
void sort(int arr[], int n);
void fillArray(int arr[], int n);
int findMin(int arr[], int n);
int findMax(int arr[], int n);
int findMode(int arr[], int n);
int range(int arr[], int n, int lower, int higher);
double findMean(int arr[], int n);
double stdDeviation(int arr[], int n, double mean);

int main(void) {
   double mean;
   int i;
   //declare an array with 500 elements
   int arr[500];
   fillArray(arr, 30);
   //print array
   printf("Original array is: ");
   print(arr, 30);
   //sort array
   sort(arr, 30);
   //print sorted array
   printf("\nSorted array is: ");
   print(arr, 30);
   printf("\nMax number is : %d\n", findMax(arr, 30));
   printf("Min number is : %d\n", findMin(arr, 30));
   mean = findMean(arr, 30);
   printf("Mean is %.2lf\n", mean);
   printf("Standard deviation is %.2lf\n", stdDeviation(arr, 30,mean));
   //range is in terms of 10 elements, ex 0-10, 11-20, 21-30
   printf("###Range####\n");
   for (i = 0; i < 100; i+=10)
   {
       printf("%d-%d: %d\n", i, i + 10, range(arr, 30, i, i+10));
   }
   return 0;
}

void print(int arr[], int n)
{
   int i;
   printf("Array is: ");
   for (i = 0; i < n; i++)
   {
       printf("%d ", arr[i]);
   }
}
void sort(int arr[], int n)
{
   int i, j, tmp;
   for (i = 0; i < n; i++)
   {
       for (j = 0; j <n-i-1; j++)
       {
           if (arr[j] >arr[j + 1])
           {
               tmp = arr[j];
               arr[j] = arr[j + 1];
               arr[j + 1] = tmp;
           }
       }
   }
}
void fillArray(int arr[], int n)
{
   int i;
   srand(time(NULL));
   for (i = 0; i < n; i++)
   {
       arr[i] = rand() % 100;
   }
}
int findMin(int arr[], int n)
{
   int min = arr[0], i;
   for (i = 0; i < n; i++)
   {
       if (min > arr[i])
       {
           min = arr[i];
       }
   }
   return min;
}
int findMax(int arr[], int n)
{
   int max = arr[0], i;
   for (i = 0; i < n; i++)
   {
       if (max < arr[i])
       {
           max = arr[i];
       }
   }
   return max;
}
int findMode(int arr[], int n)
{
   int m[100] = { 0 }, i, j, mode;

   for (i = 0; i < 100; i++)
   {
       for (j = 0; j<n; j++)
           if (arr[j] == i)
           {
               arr[i]++;
           }
   }
   mode = findMax(arr, n);
   return mode;
}

int range(int arr[], int n,int lower,int higher)
{
   int i,k=0;
   for (i = 0; i < n; i++)
   {
       if (arr[i] >= lower && arr[i] <= higher)
       {
           k++;
       }
      
   }
   return k;
}
double findMean(int arr[], int n)
{
   double sum = 0;
   int i;
   for (i = 0; i < n; i++)
   {
       sum += arr[i];
   }
   return (sum / n);
}
double stdDeviation(int arr[], int n, double mean)
{
   double sum = 0, std;
   int i;
   double m = findMean(arr, n);

   for (i = 0; i < n; i++)
   {
       sum += pow((arr[i] - mean), 2);
   }
   return sqrt((sum) / n);
}

/*Output
Original array is: Array is: 2 90 75 1 44 27 30 81 59 46 46 54 52 66 46 7 57 5 91 34 95 26 10 71 35 57 30 95 60 2
Sorted array is: Array is: 1 2 2 5 7 10 26 27 30 30 34 35 44 46 46 46 52 54 57 57 59 60 66 71 75 81 90 91 95 95
Max number is : 95
Min number is : 1
Mean is 46.47
Standard deviation is 28.57
###Range####
0-10: 6
10-20: 1
20-30: 4
30-40: 4
40-50: 4
50-60: 6
60-70: 2
70-80: 2
80-90: 2
90-100: 4

*/