Question

How many neutrons are in one atom of Sm-147 (147Sm)?

Answer 1

Atomic no is no of protons, mass no is no of nucleons, no of neutrons =A-Z.
Atomic no is no of protons, mass no is no of nucleons, no of neutrons = A - Z. The Given element is samarium (5 m) The atomic no of element is 62 Atomic Number of an element is defined as no of protons present in the nucleus of atom of an element. It is denoted by 'z'. Given, Mass Number (A) = 147 Mass Number of an element is the total no of Nuclear (Neutrons + Protons) Present in the Nucleus of atom to element. Total mass of element is concentrated at its Nucleus It is denoted by 'A'. Mass Number (A) = No. of protons + No of neutrons A = Z + N (1) Here A = Mass no, z = atomic no, N = no of Neutrons Hence the given element is _62 SM^147, A = 147, z = 62 From (1) No of Neutrons = A - Z = 147 - 62