(1 point) Find the length of the given curve. x = y3/6 + 1/(2), 14 25...
25. Given the following parametric curve X(t) = -1 + 3 cos(t) y(t) = 1 + 2 sin(t) 0<t<21 a) Express the curve with an equation that relates x and y. 7C b) Find the slope of the tangent line to the curve at the point t c) State the pair(s) (x,y) where the curve has a horizontal/vertical tangent line. 27.A particle is traveling along the path such that its position at any time t is given by r(t) =...
Problem 4, Find, for 0-x-π, the arc-length of the segment of the curve R(t) = (2 cos t-cos 2t, 2 sin t-sin 2t) corresponding to 0< t < r
Question 11 Find the length of the curve with parametric equations x = 2t, y = 3t, where 0 <t < 1. 10 42-2 O 4V2 - 1 22-1 4/ Question 12 True or false: y=x cos x is a solution of the differential equation y + y = -2 sin x True False
Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = cos(O) + sin(40) y = sin(0) + cos(40) O = 0 y(x) = Need Help? Read It Talk to a Tutor 2. [-14 Points] DETAILS SESSCALCET1 9.2.010. Consider the following: x = t3 - 12t y = 2 - 1 (a) Find the following. dy dr = dy dr2 = (b) For which values of t is the...
Given F(x, y) = (x²y3, xy). (a) Determine if F is conservative. If yes, find the scalar potential. (b) Evaluate F.dr where is the path defined parametrically by r(t) = (13 – 2t, t3 + 2t) e/F c for 0 < t < 1.
2t from Find the length of the parametric curve given by r(t) = 2 – logt and y(t) t=l to t= e.
(1 point) Find the length of the curve defined by y = 3 ln((x/3)2 – 1) from x = 6 to x = 8.
calculus 2 8. Find a parameterization of the curve y3 = x + 1, in terms of the parameter t. (2 points) b. Find the area under the curve on the range 0 < x < 1 by using an integral with respect to the parameter, t, used in part (a)(3 points)
2. Find the equation of the tangent line to the curve at the given point. x = 2 - 3 cos , y = 3 + 2 sin a t (-1,3)
At least one of the answers above is NOT correct. (1 point) Suppose f(x, t) = e 3t sin(x + 2t). (a) At any point (x, t), the differential is df = e^(-3t)cos(x+2t)dx+(e^(-3t))(2cos(x+2t)-2sin(x+2t))dt (b) At the point (-1,0), the differential is df = cos(-1)dx+(2cos(-1))+3sin(-1)dt (c) At the point (-1,0) with dx = -0.5 and dt = 0.3, the differential is df = 0.97344 Note. You can earn partial credit on this nrohlem (1 point) Consider the surface xyz = 20....