14) A train starts from rest and accelerates uniformly until it has traveled 6.4 km and...

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Answer 1

Answer #1

Q14: When the train is slowing down, the initial speed of the train, u = 21 m/s;

uniform deceleration, a = 0.065 m/s²

the final speed of the train, v =0.

Distance traveled while slowing down, s = (u² - v²) / (2*a) = ( 21² - 0² ) / ( 2* 0.065) = 3392.307 m = 3.392 km (ans)

Answer 2

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