When the play button is pressed, a CD accelerates uniformly from rest to 450 rev/min in 3.0 revolutions. If the CD has a radius of 7.0 cm and a mass of 15 g , what is the torque exerted on it? Express your answer using two significant figures.
Consider CD as a disk,
Moment of inertia is,
I = Mr2/2
= (0.015 kg)(0.07 m)2/2
= 3.675x10-5 kgm2
now,
ωf2 = ωi2 + 2αθ
[(450x2π)/(60 s)]2 = 02 + 2α(3x2π)
or, α = 58.9 rad/s2
torque is,
τ = Iα
= (3.675x10-5 kgm2)(58.9 rad/s2)
= 2.2x10-5 N.m
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