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Dado el siguiente circuito, dibuje el triángulo de potencia en la carga del secundario. Esto es, el triángulo de potencia bas

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Tellei Qovo I= Na = 2 K²=4. Fransferring and ry to Primary we gek: mm į I, . 344 Ilu I la --67784-8113 , lastjo.as + joas. TSo = va 95 - (10-918 (103) (3:344 (38)* vm 4 - (0-2% / 3 (331%/tu ) vì S23:36:43/18.435 VA = 34.56 + jllisa S= 36:43 va 1911:

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Dado el siguiente circuito, dibuje el triángulo de potencia en la carga del secundario. Esto es,...
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