Homework Answers
a)
Hypotheses are:
(b)
The test statistics is
z - 2.074
(c)
The p-value is
p-value = 0.038
(d)
Since p-value is less than alpha=0.05 so we reject the null hypothesis (H0).
(e)
Since p-value is not less than alpha=0.01 so we fail to reject the null hypothesis (H0).
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Q5. The following output from MINITAB presents the results of a hypothesis test. Test of mu...
! Required information The following MINITAB output presents the results of a hypothesis test for a...
! Required information The following MINITAB output presents the results of a hypothesis test for a population mean u. One-Sample Z: X Test of mu = 45 Vs > 45 The assumed standard deviation = 5.0921 95% Lower Bound 45.5015 Variable X N 122 Mean 46.2598 St Dev 5.0921 SE Mean 0.4610 Z 2.73 P 0.003 0.003 NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Use the output...
5. [18 points] Consider the Minitab output shown below. Test of μ = 100 vs >...
5. [18 points] Consider the Minitab output shown below. Test of μ = 100 vs > 100 The assumed standard deviation 2.4 95% Lower Bound 100.770 Mean SE Mean 101.560 3.25 25 a. Fill in the missing values in the output. Can the null hypothesis be rejected at the 0.0s level? Why? b. Is this a one-sided or a two-sided test? C. If the hypotheses had been Ho: μ = 99 versus H : μ > 99, would you reject...
Below is a selection of MiniTab output for hypothesis tests about data on homes sold in...
Below is a selection of MiniTab output for hypothesis tests about data on homes sold in Stockton, CA in the late 90s. Use this information to evaluate the hypothesis tests A) Two-tailed, c-100000, α 0.05 Descriptive Statistics N Mean StDev SEMean 95% CI for 1500 123694 63251 1633 (120490, 126897) μ mean of spruce B) Evaluate at α 0.01 Test Null hypothesis Alternative hypothesis T-Value P-Value Ho: μ-0.05 H1: μ > 0.05 240 0.008 C) Two-tailed, C-3, α-0.01 Descriptive Statistics...
A random sample of size 16 from a normal distribution with mu=3 produced a sample mean...
A random sample of size 16 from a normal distribution with mu=3 produced a sample mean of 4.5. a. Is the x distrobution normal? explain b. compute the sample test statistic z under the null hypothesis Ho: mu =6.3 c. For H1: mu <6.3, estimate the P-value of the test statistic d. For a level of significance of 0.01 and the hypothesis of parts (b) and (c), do you reject or fail to reject the null hypothesis? explain.
also should i reject or not reject? ax *, * A. .A ... AaBbCcDc AabbCcDc AaBbci...
also should i reject or not reject?
ax *, * A. .A ... AaBbCcDc AabbCcDc AaBbci AaBbcc AaB 1 Normal 1 No Spac... Heading 1 Heading 2 Title Font Paragraph Styles 17. At a water bottling facility, a technician is testing a bottle filling machine that is supposed to deliver 250 milliliters (ml.) of water. The machine is out of calibration if the mean volume differs from 250 ml. The technician wants to perform a hypothesis test to determine whether...
The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject...
The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject H when the level of significance is (a) a= 0.01, (b) a 0.05, and (c) a0.10. P 0.0749 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Reject H because the P-value, 0.0749, is greater than a=0.01 O B. Fail to reject Ho because the P-value, 0.0749, is less than a = 0.01 O C. Reject...
Pick 3 correct inferences about the following hypothesis test to determine whether the mean thickness of...
Pick 3 correct inferences about the following hypothesis test to determine whether the mean thickness of aluminum sheets equals 0.05. Assume a 5% level of significance was used. A. The null hypothesis is mean 0.05". B. This is a one-tailed test. C. The chance of a Type 1 error is 1.4%. D, 68% of sheets should be +-0.01" of Hypothesis Test (One-Sample) Sample Size Sample Mean Sample Std Dev Hypothesized Mean Data Set #1 100 0.04739 0.01043 0.05 0.05 0.00104...
Consider the following hypothesis test: Ho: mu<=12 H1: mu>12 A sample of 20 provided a sample...
Consider the following hypothesis test: Ho: mu<=12 H1: mu>12 A sample of 20 provided a sample mean of 14 and a sample standard deviation s = 4.52 . Use a = 0.05 . Step 1: Calculate the test statistic for this problem . Round your answer to four decimal places. Step 2: What is the p-value for your test? Step 3: State the conclusion to this problem.
A hypothesis test is conducted to test the null hypothesis that the mean is less than...
A hypothesis test is conducted to test the null hypothesis that the mean is less than 12. Use a 0.01 level of significance. What type of test is this? Right tail Two tail Left tail What is the critical value? 2.33 -2.33 1.78 correct answer is not given Suppose the test statistic was -2.50 What is the conclusion? Fail to reject Ho. There is not sufficent evidence to support the claim that the mean is less than 12. Reject Ho....
In order to conduct a hypothesis test for the population mean, a random sample of 28...
In order to conduct a hypothesis test for the population mean, a random sample of 28 observations is drawn from a normally distributed population. The resulting sample mean and sample standard deviation are calculated as 17.9 and 1.5, respectively. (You may find it useful to reference the appropriate table: z table or t table) H0 : μ 17.5 against HA: μ > 17.5 a-1. Calculate the value of the test statistic. (Round all intermediate calculations to at least 4 decimal...
! Required information The following MINITAB output presents the results of a hypothesis test for a population mean u. One-Sample Z: X Test of mu = 45 Vs > 45 The assumed standard deviation = 5.0921 95% Lower Bound 45.5015 Variable X N 122 Mean 46.2598 St Dev 5.0921 SE Mean 0.4610 Z 2.73 P 0.003 0.003 NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Use the output...
5. [18 points] Consider the Minitab output shown below. Test of μ = 100 vs > 100 The assumed standard deviation 2.4 95% Lower Bound 100.770 Mean SE Mean 101.560 3.25 25 a. Fill in the missing values in the output. Can the null hypothesis be rejected at the 0.0s level? Why? b. Is this a one-sided or a two-sided test? C. If the hypotheses had been Ho: μ = 99 versus H : μ > 99, would you reject...
Below is a selection of MiniTab output for hypothesis tests about data on homes sold in Stockton, CA in the late 90s. Use this information to evaluate the hypothesis tests A) Two-tailed, c-100000, α 0.05 Descriptive Statistics N Mean StDev SEMean 95% CI for 1500 123694 63251 1633 (120490, 126897) μ mean of spruce B) Evaluate at α 0.01 Test Null hypothesis Alternative hypothesis T-Value P-Value Ho: μ-0.05 H1: μ > 0.05 240 0.008 C) Two-tailed, C-3, α-0.01 Descriptive Statistics...
also should i reject or not reject?
ax *, * A. .A ... AaBbCcDc AabbCcDc AaBbci AaBbcc AaB 1 Normal 1 No Spac... Heading 1 Heading 2 Title Font Paragraph Styles 17. At a water bottling facility, a technician is testing a bottle filling machine that is supposed to deliver 250 milliliters (ml.) of water. The machine is out of calibration if the mean volume differs from 250 ml. The technician wants to perform a hypothesis test to determine whether...
The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject H when the level of significance is (a) a= 0.01, (b) a 0.05, and (c) a0.10. P 0.0749 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Reject H because the P-value, 0.0749, is greater than a=0.01 O B. Fail to reject Ho because the P-value, 0.0749, is less than a = 0.01 O C. Reject...
Pick 3 correct inferences about the following hypothesis test to determine whether the mean thickness of aluminum sheets equals 0.05. Assume a 5% level of significance was used. A. The null hypothesis is mean 0.05". B. This is a one-tailed test. C. The chance of a Type 1 error is 1.4%. D, 68% of sheets should be +-0.01" of Hypothesis Test (One-Sample) Sample Size Sample Mean Sample Std Dev Hypothesized Mean Data Set #1 100 0.04739 0.01043 0.05 0.05 0.00104...
In order to conduct a hypothesis test for the population mean, a random sample of 28 observations is drawn from a normally distributed population. The resulting sample mean and sample standard deviation are calculated as 17.9 and 1.5, respectively. (You may find it useful to reference the appropriate table: z table or t table) H0 : μ 17.5 against HA: μ > 17.5 a-1. Calculate the value of the test statistic. (Round all intermediate calculations to at least 4 decimal...
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