Question

Question 11 Construct the indicated confidence interval for the difference between population proportions. Assume that the samples are independent and that they have been randomly selected. Not yet answered Points out of 1.00 Flag question A marketing survey involves product recognition in New York and California. Of 558 New Yorkers surveyed, 193 knew the product while 196 out of 614 Californians knew the product. Construct a 99% confidence interval for the difference between the two population proportions. Select one: 0.0247 <P4 -P2 <0.0286 -0.0443<p, -p, < 0.0976 -0.0034 < p, -p, <0.0566 -0.0177 <P, -p, <0.1243 Question 12 Construct the indicated confidence interval for the difference between population proportions. Assume that the samples are independent and that they have been randomly selected. Not yet answered Points out of 1.00 In a random sample of 500 people aged 20-24, 22% were smokers. In a random sample of 450 people aged 25-29, 14% were smokers. Construct a 95% confidence interval for the difference between the population proportions p. - P. P Flag question Select one: 0.048 <P1 - P2 <0.112 O 0.035<P, -P2 <0.125 0.025<P, -P2 <0.135 0.032<P, -P2 <0.128

11. Construct the indicated confidence interval for the difference between population proportions. Assume that the samples are independent and that they have been randomly selected.

A marketing survey involves product recognition in New York and California. Of 558 New Yorkers surveyed, 193 knew the product while 196 out of 614 Californians knew the product. Construct a 99% confidence interval for the difference between the two population proportions.

12. Construct the indicated confidence interval for the difference between population proportions. Assume that the samples are independent and that they have been randomly selected.

In a random sample of 500 people aged 20-24, 22% were smokers. In a random sample of 450 people aged 25-29, 14% were smokers. Construct a 95% confidence interval for the difference between the population proportions p₁ − p₂.

13. Find the degrees of freedom, df to test the hypothesis that μ₁ > μ₂. Two samples are randomly selected and come from populations that are normal. The sample statistics are given below.
n₁ = 43          n₂ = 43
= 63.0       = 61.5
s₁ = 11.9          s₂ = 23.4

Thank you !!!

Answer 1

® n= 558 , ß, - 1338 m2 = 614, pz = b For 99.4. confidence, Z-value = 2.57583 :. The 994. confidence interval for the difference = (Ếi – ) Ł Z PCI-E) + (B2) = (-0.044 322, 0.097642) z (-0.0443, 0.0976) → 10.0443 < Pi - Px < 0.09767 n2 2 n, = 500, Ñ, = 0.22 n2 = 450, Ấ2 = 0.14 For 95'1. confidence, Z-value = 1.95996 :. The 951. confidence interval for the difference = (P. – B) + z Pi () + B(1-B) - nz = (0.03156, 0.12843) ~ (0.032, 0.128) 0.032 < Pi-P2 < 0.128 +

13 The degrees of freedom: df (silni + 52/M2)² (55/M.)² + (52 m.)² ni-l n2-1 (11.9243 + 23.473) (11.9°/43) (23.4²/43) 43-1 = 62.3621 162] (rounded down)