Question

Disable the shields 38. The electron beam you made works and the probe is now visible to all the Starship Disoovery's sensors. It's nat good news though...The probe has advanced electramagnetic shields that keep changing frequency that could only have come from the future! You use MATLAB to write a program to analyse the shield's frequency changes and discover a weakness in the shields at 1880 THz. Calculate the wavelength, in nano-metres (nm) of laser photons needed to disable the shields. nm 1 mark) Destroy the probe and save the Discovery 39. While your laser beam does work, the shields adapt every second and change frequency; you do, however, find that you will need an explosion of 400 mega-joules (MJ) to destroy the probe, based on sensor readings, You only have one photon torpedo left to destroy the probe and save the Starship Discovery. The maximum energy of the photons is 4.8 eV. When you next disrupt the shields, the torpedo needs to deliver this energy to the probe to destroy it. How many photons need to be absorbed by the probe in one second to destroy it?

Answer 1

We know the equation connecting frequency and wavelength, v = nu lambda where v rightarrow velocity of wave, nu rightarrow frequency of wave, lambda rightarrow wavelength of wave . since we use photon laser here v = velocity of light = 3 times 10^8 m/s Given nu = 1880 TH_z = 1880 times 10^12 Hz Therefore wavelength lambda = v/nu = 3 times 10^8/1880 times 10^12 = 159 . 57 nm 39) Given energy required to destroy = 400 mj Energy of one photon = 4 . 8 ev = 4 . 8 times 1 . 60218 times 10^- 19 j Therefore No . of photons required = 400 times 10^6/4 . 8 times 1 . 60218 times 10^- 19 = 5 . 20125 times 10^26 photons