Please solve the study question #3.
Please solve the study question #3. ALL for your work y" + 6y' + 5y =...
(1 point) Take the Laplace transform of the following initial value problem and solve for Y(8) = L{y(t)}; ſ1, 0<t<1 y" – 6y' - 27y= { O, 1<t y(0) = 0, y'(0) = 0 Y(8) = (1-e^(-s)(s(s^2-6s-27)) Now find the inverse transform: y(t) = (Notation: write uſt-c) for the Heaviside step function uct) with step at t = c.) Note: 1 | 1 s(8 – 9)(8 + 3) 36 6 10 + s $+37108 8-9
Q1) Solve the following DE: (Using Laplace transform is recommended) y" + 5y' – 6y = f(t), y(0) = 0, y'(0) = 0, where 0 <t< 2 f(t) = {-4 t>2 1
Use the Laplace transform to solve the given initial-value problem. y" + 6y' + 5y = 0, y(0) = 1, y'(O) = 0 y(t) =
please solve with steps and explain thanks
Question 5 Given the differential equation y'' + 5y' + 4y = 0, y(0) = 2, y'(0) = 1 Apply the Laplace Transform and solve for Y(8) = L{y} Y(8) = Now solve the IVP by using the inverse Laplace Transform y(t) = L-'{Y(s)} g(t) =
Question 5 < > Given the differential equation y' + 5y' + 4y = 0, y(0) = 2, y'(0) = 1 Apply the Laplace Transform and solve for Y(8) = L{y} Y(s) = Now solve the IVP by using the inverse Laplace Transform y(t) = L-'{Y(s)} g(t) =
13. Use the Laplace transform to solve the initial value problem: (&pts) y" - 6y' + 5y = 3e, y(0) = 2, 7(0) = 3
1. Solve using the Laplace transform y" − 6y' + 18y = 36 y(0) = 1, y'(0) = 6 3. Solve t f(t)−cos2t + ∫ f(τ)sin(t−τ)dτ =1 0
Consider the following initial value problem. y" + 6y' + 34y = 8( - 1T) + 6(t – 7), 7(0) = 1, y(0) = 0 Find the Laplace transform of the differential equation. (Write your answer as a function of s.) Use the Laplace transform to solve the given initial-value problem. y(t) = ])-( * sin(70) .).2(e-) + ( [ - alt- Need Help? Read it Talk to a Tutor
Solve the following differential equation with given initial conditions using the Laplace transform. y" + 5y' + 6y = ut - 1) - 5(t - 2) with y(0) -2 and y'(0) = 5. 1 AB I
Page 2 II. (7) Use the Laplace transform to solve the IVP y" - 5y' + 6y = 8(t-1), y(0) = 0,0) = 0, where the right hand side is the Dirac Delta Function (t - to) for to = 1. You may use the partial fraction decomposition 1 + 52-58 +6 2 S-3 but you need to show all the steps needed to arrive to the expression 1 52-58 +6 in order to receive credit. f(t)=L-'{F(s) Table of Laplace...