Question

20 T2 (s) 4.54 2 120 Periods (s) T (s) L (cm) 5 120 I.a9 39 g0 35 29 3o. 86 25.14 17.93 100 6o ㄐ〇 20 0 1-5y .24 900 3.13 2.37
Plot the period T vs. the length L for the second set of data. Be sure to select the line connecting the points option. Make
zs the regression line close to the data points? Slope from the T2 Vs. L graphーーーーーーーーーーー The theoretical value of the slope
0 0
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Answer #1

Both the graphs has been plotted using origin

Graph 1: T versus L

Black colour shows the actual data, Red line shows the linear fit of the data.

2.5 Equation Weight Residual Sum 0.31829 Pearsonsr y= a + bX No Weightng ()또ar// 2.0 AR-Square 8838 aStandard Error Intercep

Yes. the graph is a straight line. It shows that the T is directly proportional to L.

By linear fitting of the data,

T= 0.01621L+0.39714

Where. 0.01621 s/m is the slope of the line and 0.39714 s is the intercept.

Graph 2: T2 versus L

Linear Fit of Sheet1 BT Weighting Weight Residual Sum 002079 of Squares Pearsonsr 0.99937 4 Adj R-Square 09849 Value Sanda

YYes, Regression line is very much close to the data points.

Slope of the graph= 0.03832 s2/ cm

Percent Difference:

0.03832-0.040 0.040 Percent × 100 = 4.2

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