Question

I would like to know how the part boxed in on the picture is solved? If possible can you write steps on solving using TI N Spire also?

Test for Normality Use chi-square to determine if the variable shown in the frequency distribution is normally distributed. Use a 0.05, 4. Boundaries 89.5 104.5 104.5-119.5 119.5-134.5 134.5 -149.5 149.5- 164.5 164.5-179.5 Frequency 24 62 72 26 12 4 State the hypothesis Ho: The variable is normally distributed Ha: The variable is not normally distributed Find the critical value. The critical value has the degrees of freedom equal to the number of categories minus 3 since 1 degree of freedom is lost for each parameter that is estimated. In this case, the mean and standard deviation have been estimated, so two additional degrees of freedom are needed. Degrees of freedom = 5-3-2. XO-5991 Compute the test value. Find the mean and standard deviation of the variable (the sample standard deviation, s is used to approximate the population standard deviation, sigma, X-123.4, s 17.03 Find the area under the normal distribution: x < 104.5 0.1335 104.5 < x < 119.5 0.2755 119.5 <x< 134.5 0.3332 134.5 < x < 149.5 0.1948 149.5 <x< 164.5 0.0550 x > 164.5 0.0080 Find the expected frequencies for each class 0.1335 200 26.7 0.2755 200 55.1 0.3332* 200 66.64 0.1948 200 38.96 0.0550 * 200 = 11.0 0.0080 *200 1.6

Answer 1