Solution:
We have given information, | |||||||||
Distance to work(X) | Number of days absent(Y) | ||||||||
1 | 8 | ||||||||
3 | 5 | ||||||||
4 | 8 | ||||||||
6 | 7 | ||||||||
8 | 6 | ||||||||
10 | 3 | ||||||||
12 | 5 | ||||||||
14 | 2 | ||||||||
14 | 4 | ||||||||
18 | 2 | ||||||||
Let Y be the dependent variable (number of days absent) and X be the independent variable(distance to work). | |||||||||
The sample regression equation is given as, | |||||||||
Y = a + b*X + e | |||||||||
Here, a is the intercept coefficient and b is the slope coefficient. | |||||||||
and e is an error term | |||||||||
The OLS regression line is given as, | |||||||||
Y = a + b*X | |||||||||
The OLS regression line is obtained by the following Excel steps: | |||||||||
1. click the data tab in the ribbon and then click on data analysis tab. | |||||||||
2. select regression and select independent and dependent variable data | |||||||||
3. put the confidence level and output range then we get the following values | |||||||||
SUMMARY OUTPUT | |||||||||
Regression Statistics | |||||||||
Multiple R | 0.843121469 | ||||||||
R Square | 0.710853812 | ||||||||
Adjusted R Square | 0.674710539 | ||||||||
Standard Error | 1.289414821 | ||||||||
Observations | 10 | ||||||||
ANOVA | |||||||||
df | SS | MS | F | Significance F | |||||
Regression | 1 | 32.69927536 | 32.69927536 | 19.66766549 | 0.002182936 | ||||
Residual | 8 | 13.30072464 | 1.66259058 | ||||||
Total | 9 | 46 | |||||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | ||
Intercept | 8.097826087 | 0.808822137 | 10.01187494 | 8.4133E-06 | 6.232678894 | 9.96297328 | 6.232678894 | 9.96297328 | |
Distance to work(X) | -0.344202899 | 0.077613652 | -4.434824178 | 0.002182936 | -0.5231803 | -0.165225497 | -0.5231803 | -0.165225497 | |
The estimated regression line is given as, | |||||||||
Y = 8.0978 - 0.3442* X | |||||||||
The predicted number of days when the value of X = 7 and X = 13 is given as, | |||||||||
Y (predicted number of absent days) | X (distance in miles) | ||||||||
5.6884 | 7 | ||||||||
3.6232 | 13 | ||||||||
Therefore, the required predicted value in the above table. | |||||||||
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