5. The 1H-NMR, 13C-NMR and MS spectrums of an unknown compound are shown below. The molecular formula of the compound is C7H14O. What is the structure of the unknown?
Homework Answers
The H-NMR shows three peaks which means the compound has three non equivalent hydrogens. The C-NMR shows four peaks which means it has four non equivalent carbons.
By H-NMR, the total hydrogens are 3H + 2H + 2H = 7H. Since the molecule has 14H (as given by the molecular formula C7H14O), this means ithas symmetrical hydrogens.
By (n+1) rule, Triplet of 3H (2+1) signifies peak of CH3CH2-.
By (n+1) rule, Triplet of 2H (2+1) signifies peak of -CH2CH2-.
By (n+1) rule, Sextet of 2H (5+1) signifies peak of -CH2CH2CH3.
By C-NMR, peak beyond 200 signifies C=O group.
The compound is dipropyl ketone. The structure of it is given as
It has 3 non equivalent hydrogens which are represented as (a), (b) and (c) in the figure below
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