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10Q 8. Scores on an examination are assumed to be normally distributed with mean 68 and variance 49 (a) What is the probabili

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1Date: solution :- le=68 6=7 ay p(x >61) = l-P(x<61). - 18(8-4< 61-68) =I-PL ZL-D - -01589 = 0.8413 probability c 0.8413 - P(Z

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