Question

Problem 1 The figure shows a 2.0 kg block compressing a 5,000 N/mspring by 0.10 m. After the block is released from rest it first encounters a 3.0 m frictional surface, followed by a frictionless hill. The coefficient of friction between the block and the surface is 0.36. un Frictional Surface A) Find the speed of the block just before it reaches the frictional surface. (7 pts.) m=2kg B) Find the speed of the block at the end of the frictional surface. (7 pts.) 5. OUDY C) Find the maximum height that the block will reach on the frictionless hill. 17 pts.) Aroha : D) Find the final resting position for the mass (7 pts.) 023 m E) Find the initial mechanical energy of the system. (4 pts.) F) Find the energy loss due to friction during the first pass over the frictional surface. (4 pts.) UKO G) Find the energy loss due to friction during the return pass over the frictional surface. (4 pts.)

Answer 1

(A) - 3m 4, By Conservetion of cncrgy kx = 2. x 5000 x (0L) 2 = Lx 2xu2 5 mlden => fnchion sorface accelerapion. 0.36 x 9.8 3.528 m/s2 %3D . v²= u?+2ad v²- (5) 2x3.528X3 1.96 m dee

heyht Maximem + 203 wring v-ニu2 B, (1.96) +2(-9.8) () 0.1955 m 0.2 m. fronly and will finaly it down will Come Stop frichional sorface moion u = 1:96 m pesi han v-o m/dee Resting V2= using =42+ 2asc 2. (196) + 2(-49) x (196) 0.54 m 2メ 0.36×9.8 Come to stop af o:54 m it will So from nght cng of frepmy Romp.

(E) Initiog Imuz Eneryy mechanicd 2. or 25 J Ei in frot pors E lost (F) DE, **2(5= 196") AE, 21.16 J %3D encryy will frichoned mech amical (G) Rest of be lost in return pars over the Swface (25-21:16) J 3. 84 5 %3D