Question

G the rib labeled - Google Searc! X Skeletal System Axial Skeleton + - SPSS ANOV... Jamica Davis JD - References Mailings Review View Help Search me insert Design Layout Times New Roman 12 BIUab , XA A-D-A- Aa A A Styles Editing Dictate EEE 13 2 1 Paragraph Font Styles 2. A Psychologist at a private psychiatric hospital was asked to determine whether there was any clear difference in the length of stay of patients with different categories of diagnosis Looking at patients in the three major categories, the results (in weeks) were as follows: Affective Cognitive Drug Related 11 GO a State your null and alternative hypotheses in words. (2 pts) b. What are the three DFs? (Groups. Between Error Within, Total). What is your Critical F? (4 pts) c. What is the Calculated F? (3 pts) d. Was it significant? What is the significance value? (2 pts) e. Do you reject or fail to reject the null hypothesis? What is your conclusion? (2 pts) 313 words Facu in Excel Ms Office? ^ D 12:45 PM 10/6/2019 ho

Answer 1

a)

Claim: There is a difference in the length of stay of patients with different categories of diagnosis.

The null and alternative hypothesis is:

$H0:\mu1=\mu2=\mu3$

H1: At least one of the mean is different.By using excel we can solve this question easily.

First, enter all data into excel.

Click on Data -------> Data Analysis--------> Anova: Single-Factor-----> Input Data -------> Select all data -------> Output Range : Select any empty cell --------> ok

We get

- x New Microsoft Office Excel Worksheet - Microsoft Excel Team o - X E show Detail Data Analysis Clear Reapply Advanced HEEG... 41 41 3 = Home Insert Page Layout Formulas Data Review View Connections 2 AZ Properties From From From From Other Existing Refresh At Sort Access Web Text Sources Sources Connections Connections All Edit Links Get External Data Connections 010 - fi A B C D E Hide Detail - Group Ungroup Subtotal Filter Text to Remove Data Consolidate What If Columns Duplicates Validation Analysis Data Tools Sort & Filter Outline Analysis J K L M N P Q R S Affective Congnitivi Drug-Related 12 8 10 Anova: Single Factor Count SUMMARY Groups Affective Congnitive Drug-Related Sum Average Variance 54 1.5 96 10.66667 3.5 100 11.11111 5.361111 9 5 9 9 df ANOVA Source of Variation Between Groups Within Groups SS 144.2963 82.88889 MS 2 72.14815 24 3.453704 F P-value Fcrit 20.89008 5.56E-06 3.402826 Total 227.1852 26 24 25 Ke Ready Activate Windows Go to PC settings to activate Windows Sheet1 Sheet2 Sheet30 O 100% e o 29 ® © EA x 01 102 - JDOOR 9.10 persons 0 11:35 PM 10/06/2019

b)

DFs for groups/Between = 2

DFs for error/within = 24

DFs for total = 26

Critical F = 3.403

c)

Calculate F = 20.890

d)

Level of significance = 0.05

P-value = 0.00000556

P-value < 0.05 we reject null hypothesis.

e)

Calculated F > Critical F we reject null hypothesis.

Conclusion:

At one of the mean is different.